We know the importance of the Bar Bending Schedule and have already discussed it.
Here we are going to see the Bar Bending Schedule for Beam. It’s not totally different from slab calculation.
Before starting the topic make sure that you have read the below topics
We will discuss this scheduling topic as two parts, one for a typical beam and one for detailed design specification.
Let’s start.
From the diagram, we can extract the below data
Cutting Length of Top Bar = Lclear + 2 x Development Length = 2600 + (2x50x12) = 3800 mm
Cutting Length of Bottom Bar = Lclear + 2 x Development Length = 2600 + (2x50x16) = 4200 mm
Number of Stirrups = Lclear / Spacing +1 = 2600/200 = 13+1 = 14 Nos
Cutting Length of Stirrups = Sum of total lengths (excluding cover) – 3 nos of 90° bends – 2 nos of 135° bends + 2 nos of Hook Length
We have a detailed post about cutting length of stirrups.
Assuming Length of one hook = 9d
Cutting Length of Stirrups = (520+250+520+250)-(3 x 2d)-(2 x 3d)+(2x9d) = 1540-(3x2x8)-(2x3x8)+ (2x9x8) = 1588 mm
Cutting Length of Stirrups = 1588 mm or 1.59 m
Description | Dia of Bar (mm) | Number of Bars | Cutting Length | Weight Per metre | Total Quantity (Kg) |
Top Reinforcement | 12 | 2 | 3.8 | 0.89 | 6.764 |
Bottom Reinforcement | 16 | 2 | 4.2 | 1.58 | 13.272 |
Stirrups | 8 | 14 | 1.59 | 0.4 | 8.904 |
TOTAL | 28.94 Kg |
Sometimes beams will come up with an extra one crank bar at the centre as shown in the diagram below.
From the diagram, we can extract the below data
Cutting Length of Top Bar = Lclear + 2 x Development Length = 2600 + (2x50x12) = 3800 mm
Cutting Length of Bottom Bar = Lclear + 2 x Development Length = 2600 + (2x50x16) = 4200 mm
Cutting Length of Bottom Crank Bar = Lclear + (2 x 0.42H)+ (2 x 45° bend) + (2 x Development Length)
Length of crank bar = 0.42 H
Where, H = Beam Depth – Concrete Cover – dia of bar = 600 – (2×40) – 16 = 504 mm
Cutting Length of Bottom Crank Bar = 2600 + (2×0.42×504) + (2x1d) + (2 x 50d)
= 2600 + (2 x 0.42 x 504) + (2 x 1 x 16) + (2 x 50 x 16) = 4655.36 mm or 4.66 m
Number of Stirrups = Lclear / Spacing +1 = 2600/200 = 13+1 = 14 Nos
Cutting Length of Stirrups = Sum of total lengths (excluding cover) – 3 nos of 90° bend – 2 nos of 135° bend + 2 nos of Hook Length
Assuming Length of one hook = 9d
= (520+250+520+250) – (3 x 2d) – (2 x 3d) + (2x9d) = 1540 – (3x2x8) – (2x3x8) + (2x9x8) = 1588 mm
Cutting Length of Stirrups = 1588 mm or 1.59 m
Bar Bending Schedule – Beam Format
Description | Dia of Bar (mm) | Number of Bars | Cutting Length | Weight Per metre | Total Quantity (Kg) |
Top Reinforcement | 12 | 2 | 3.8 | 0.89 | 6.764 |
Bottom Reinforcement | 16 | 2 | 4.2 | 1.58 | 13.272 |
Bottom Crank Bar | 16 | 1 | 4.66 | 1.58 | 7.363 |
Stirrups | 8 | 14 | 1.59 | 0.4 | 8.904 |
TOTAL | 36.30 Kg |
Happy Learning 🙂
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