We know the importance of the Bar Bending Schedule and have already discussed it.

**Contents of the Article**show

Here we are going to see the Bar Bending Schedule for Beam. Itâ€™s not totally different from slab calculation.

Before starting the topic make sure that you have read the below topics

- Why steel is used in Concrete?
- Bar Bending Shape Codes
- What is Development Length and Lap Length?
- Types of Stirrups in Reinforcement

We will discuss this scheduling topic as two parts, one for a typical beam and one for detailed design specification.

Letâ€™s start.

**Bar Bending Schedule for a Typical Beam**

From the diagram, we can extract the below data

**Given Data**

- Beam Size â€“ 600 x 300 x 2600Â mm
- Bottom Reinforcement 16mm of 2 numbers
- Top Reinforcement 12mm of 2 numbers
- Stirrups â€“ 8mm of 200 c/c
- Concrete cover â€“ 25 mm @ sides & 40mm @ top & bottom
- Development Length as 50d (assumption)

**Step 1 â€“ Find Cutting Length of Top & Bottom Bars**

Cutting Length of Top Bar = Lclear + 2 x Development Length = 2600 + (2x50x12) = 3800 mm

Cutting Length of Bottom Bar = Lclear + 2 x Development Length = 2600 + (2x50x16) = 4200 mm

**Step 2 â€“ Find Number of Stirrups**

Number of Stirrups = Lclear / Spacing +1 = 2600/200 = 13+1 = 14 Nos

**Step 3 â€“ Find Cutting Length of Stirrups**

Cutting Length of Stirrups = Sum of total lengths (excluding cover) â€“ 3 nos of 90Â° bends â€“ 2 nos of 135Â° bends + 2 nos ofÂ Hook Length

We have a detailed post about cutting length of stirrups.

Assuming Length of one hook = 9d

Cutting Length of Stirrups = (520+250+520+250)-(3 x 2d)-(2 x 3d)+(2x9d) = 1540-(3x2x8)-(2x3x8)+ (2x9x8) = 1588 mm

Cutting Length of Stirrups = 1588 mm or 1.59 m

**Bar Bending Schedule â€“ Beam Format**

Description |
Dia of Bar (mm) |
Number of Bars |
Cutting Length |
Weight Per metre |
Total Quantity (Kg) |

Top Reinforcement | 12 | 2 | 3.8 | 0.89 | 6.764 |

Bottom Reinforcement | 16 | 2 | 4.2 | 1.58 | 13.272 |

Stirrups | 8 | 14 | 1.59 | 0.4 | 8.904 |

TOTAL |
28.94 Kg |

**Bar Bending Schedule for Detailed Beam**

Sometimes beams will come up with an extra one crank bar at the centre as shown in the diagram below.

From the diagram, we can extract the below data

**Given Data**

- Beam Size â€“ 600 x 300 x 2600Â mm
- Bottom Reinforcement 16mm of 2 numbers
- Crank bar at bottom reinforcement 16mm of 1 number
- Top Reinforcement 12mm of 2 numbers
- Stirrups â€“ 8mm of 200 c/c
- Concrete cover â€“ 25 mm @ sides & 40mm @ top & bottom
- Development Length as 50d (assumption)

**Step 1 â€“ Find Cutting Length of Top & Bottom Bars**

Cutting Length of Top Bar = Lclear + 2 x Development Length = 2600 + (2x50x12) = 3800 mm

Cutting Length of Bottom Bar = Lclear + 2 x Development Length = 2600 + (2x50x16) = 4200 mm

Cutting Length of Bottom Crank Bar = Lclear + (2 x 0.42H)+ (2 x 45Â° bend) + (2 x Development Length)

Length of crank bar = 0.42 H

Where, H = Beam Depth â€“ Concrete Cover â€“ dia of bar = 600 â€“ (2Ã—40) â€“ 16 = 504 mm

Cutting Length of Bottom Crank Bar = 2600 + (2Ã—0.42Ã—504) + (2x1d) + (2 x 50d)

= 2600 + (2 x 0.42 x 504) + (2 x 1 x 16) + (2 x 50 x 16) = 4655.36 mm or 4.66 m

**Step 2 â€“ Find Number of Stirrups**

Number of Stirrups = Lclear / Spacing +1 = 2600/200 = 13+1 = 14 Nos

**Step 3 â€“ Find Cutting Length of Stirrups**

Cutting Length of Stirrups = Sum of total lengths (excluding cover) â€“ 3 nos of 90Â° bend â€“ 2 nos of 135Â° bend + 2 nos of Hook Length

Assuming Length of one hook = 9d

= (520+250+520+250) â€“ (3 x 2d) â€“ (2 x 3d) + (2x9d) = 1540 â€“ (3x2x8) â€“ (2x3x8) + (2x9x8) = 1588 mm

Cutting Length of Stirrups = 1588 mm or 1.59 m

**Bar Bending Schedule â€“ Beam Format**

Description |
Dia of Bar (mm) |
Number of Bars |
Cutting Length |
Weight Per metre |
Total Quantity (Kg) |

Top Reinforcement | 12 | 2 | 3.8 | 0.89 | 6.764 |

Bottom Reinforcement | 16 | 2 | 4.2 | 1.58 | 13.272 |

Bottom Crank Bar | 16 | 1 | 4.66 | 1.58 | 7.363 |

Stirrups | 8 | 14 | 1.59 | 0.4 | 8.904 |

TOTAL |
36.30 Kg |

Happy Learning ðŸ™‚