Today we are going to discuss brickwork calculation. We are going to find out the below for 1m^{3} of brickwork

- Number of bricks
- Required cement quantity
- Required sand quantity

**Table of Content**hide

**Brickwork Basics**

- Size of the Bricks – 190mm x 90mm x 90mm

For calculation, purposes convert the Size of bricks into Meter.

So now the measurement is 0.19m x 0.09m x 0.09m

Therefore Volume of 1 brick = 0.001539 m^{3}

**Brickwork Calculation Formula**

**STEP 1 – Volume of single brick without mortar**

Volume of 1 brick without mortar = 0.19 x 0.09 x 0.09 = 0.0015 m^{3}

**STEP 2 – Volume of single brick with mortar**

While brickwork construction we will add cement mortar around 3 sides (left, right & top).

So adding 10mm thick on each side of brick as mortar thickness

The volume of brick with mortar = (0.19+0.010) x (0.09+0.010) x (0.09+0.010) = 0.20 x 0.1 x 0.1 = 0.002 m^{3}

The volume of 1 brick with mortar = 0.002 m^{3}

**STEP 3 – Number of bricks for 1 m ^{3} Brickwork**

Number of bricks with mortar for 1 m3 = 1 cubic meter / volume of bricks with mortar = (1/0.002)= 500 Nos

So the required number of bricks for 1 m^{3} = 500 Nos

**STEP 4 – Cement Mortar Volume for 1m ^{3} of Brickwork**

Cement Mortar Volume = Volume of brickwork with mortar – the volume of bricks without mortar

Volume of bricks with mortar in 1 m^{3} = 500 x 0.002 = 1 m^{3}

Volume of bricks without mortar in 1 m^{3} = 500 x 0.001539 = 0. 7695 m^{3}

Therefore required cement mortar = 1 m^{3} – 0.7695 m^{3} = 0.2305 m^{3}

**Step 5 – Calculate Cement & Sand Volume**

As we know the required cement mortar = 0.2305 m^{3}

Assuming cement mortar ratio as 1:5 (1 Part Cement: 5 Part Sand)

We have already discussed the cement mortar volume calculation in the plastering work post.

The above formula will give the dry volume of cement mortar, So to get wet concrete volume, we have to multiply the dry volume by 1.55

Total Parts = 1+5 =6

Required Volume of Cement = 1/6 x 1.55 (void ratio) x Mortar Volume = 1/6 x 1.55 x 0.2305= 0.0595 m^{3}

To convert into cement bags – (0.0595 x 1440)/50 = 1.71 Bags or 85.68 Kg

Required Sand Volume = 5/6 x 1.55 (void ratio) x Mortar Volume = 5/6 x 1.55 x 0.2305 = 0.298 m^{3}

**Result**

Materials required for 1 m^{3} Brickwork is

- 500 Numbers of bricks
- 85.68 kg or 1.71 Bags of cement
- 0.298 m
^{3 }of sand

Make Use of this brickwork calculator

Hope you learned something from this post. Happy day 🙂

## 1 Comment

For cement mortar the dry volume factor to be considered is 1.33 not 1.55