We have already discussed the importance of rate analysis. and how it will help us to face everyday scenarios.

## Estimation of Material Quantity

Assume that we are going to analysis the rate for **1 Cum of Brickwork** (B.W)

**STEP 1 – Volume of single brick without mortar**

Volume of 1 brick without mortar = 0.19 x 0.09 x 0.09 = 0.0015 m^{3}

**STEP 2 – Volume of single brick with mortar**

While brickwork construction we will add cement mortar around 3 sides (left, right & top).

So adding 10mm thick on each side of brick as mortar thickness

The volume of brick with mortar = (0.19+0.010) x (0.09+0.010) x (0.09+0.010) = 0.20 x 0.1 x 0.1 = 0.002 m^{3}

Volume of 1 brick with mortar = 0.002 m^{3}

**STEP 3 – Number of bricks for 1 m3 Brickwork**

Number of bricks with mortar for 1 m3 = 1 cubic meter / volume of bricks with mortar = (1/0.002)= 500 Nos

So the required number of bricks for 1 cum = 500 Nos

**STEP 4 – Cement Mortar Volume for 1m3 of Brickwork**

Cement Mortar Volume = Volume of brickwork with mortar – volume of bricks without mortar

Volume of bricks with mortar in 1 Cum = 500 x 0.002 = 1 m^{3}

Volume of bricks without mortar in 1 Cum = 500 x 0.001539 = 0. 7695 m^{3}

Therefore required cement mortar = 1 cum – 0.7695 cum = 0.2305 m^{3}

**Step 5 – Calculate Cement & Sand Volume**

As we know the required cement mortar = 0.2305 m^{3}

Assuming cement mortar ratio as 1:5 (1 Part Cement : 5 Part Sand)

We have already discussed the cement mortar volume calculation in plastering work post.

The above formula will give a dry volume of cement mortar, So to get wet concrete volume, we have to multiply the dry volume by 1.33

**Total Parts = 1+5 =6**

Required Volume of Cement = 1/6 x 1.33 x Mortar Volume = 1/6 x 1.33 x 0.2305= 0.0511 m^{3}

To convert into cement bags – (0.0511 x 1440)/50 = 1.47 Bags or 73.58 Kg

Required Sand Volume = 5/6 x 1.33 x Mortar Volume = 5/6 x 1.33 x 0.2305 = 0.2554 m^{3}

**Required Material Quantity**

Materials required for 1 m3 Brickwork is

- 500 Numbers of bricks
- 73.58 Kg or 1.47 Bags of cement
- 0.2554 m
^{3 }of sand

**Labour Estimation**

From our thumb rule estimation (Labour Output Per Day), we are calculating the labour estimation as follow,

- Mason / Brick Layer – 0.4
- Male Coolie – 0.5
- Female Coolie – 0.5
- Waterman – 0.2

Description |
Unit |
Qty |
Rate |
Amount |

Analysis of the rate for 1 Cum of Brick Work (B.W) in Cement Mortar 1:5 (1 Cement: 5 coarse sand) using common burnt clay bricks of class designation 75, including curing, etc. | ||||

Materials |
||||

Cement | Bags | 1.47 | 350 | 514.5 |

Sand | Cum | 0.2554 | 1800 | 459.72 |

Bricks including wastage | Nos | 500 | 7 | 3500 |

Manpower |
||||

Mason | Each | 0.4 | 700 | 280 |

Male Mazdoor | Each | 0.5 | 500 | 250 |

Female Mazdoor | Each | 0.5 | 400 | 200 |

Waterman | Each | 0.2 | 400 | 80 |

Subtotal |
5284 |
|||

Tools & Tackles | 1% | 53 | ||

Add for Sundries & Contingencies | 3% | 158.5 | ||

Add for Over head & Contractor profit | 10% | 528 | ||

Total |
6023.5 |
|||

Rate per Cum |
6023.5 |

**You may download the Excel Sheet of Rate Analysis: Rate Analysis Sheet**